0=3x^2+9x+3

Solution for 0=3x^2+9x+3 equation:

0=3x^2+9x+3

We move all terms to the left:

0-(3x^2+9x+3)=0

We add all the numbers together, and all the variables

-(3x^2+9x+3)=0

We get rid of parentheses

-3x^2-9x-3=0

a = -3; b = -9; c = -3;
Δ = b2-4ac
Δ = -92-4·(-3)·(-3)
Δ = 45
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{45}=\sqrt{9*5}=\sqrt{9}*\sqrt{5}=3\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-3\sqrt{5}}{2*-3}=\frac{9-3\sqrt{5}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+3\sqrt{5}}{2*-3}=\frac{9+3\sqrt{5}}{-6}
$